In case anybody was wondering, I'm still alive. I've been inordinately busy lately and have been spending the majority of my free time online re-learning Ruby on Rails. I've also been digging into multi-master and circular replication schemes for MySQL and MySQL proxy. I plan on sharing some of the things I've learned sometime in the near future. Anyway, here's a handy tip that I just used this morning.
If you want to sort all the files in a directory by size, you can do the following:
ls -lsR | sort -nr
The sort command will order by the number of blocks in each file. The biggest files are at the top.
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3 comments:
I just use 'ls -rS' here. No?
I often do:
$ ls -l | sort -k5,5 -n
As Steve writes, the -S option is the key. These are all good:
ls -S
ls -sS
ls -lS
They give just the filenames, just file size and name, and the full long listing respectively, with the biggest file at the top.
I often combine it with head:
ls -lS | head
ls -lS | head -20
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