Now for some fun ;-). A friend asked me for a Vim macro this morning to strip all but the text contained with the double quotes of a file with the following format:
<option value="Automotive">Automotive</option>
<option value="Banking">Banking</option>
<option value="Biotech">Biotech</option>
etc...
After the macro it would be:
Automotive
Banking
Biotech
etc...
Initially, I came up with the following sequence (macro storage command omitted):
df"f"d$j0 (9 chars)
This works fine, but my OCD kicked in, and I decided to make it shorter:
df"f"D+ (7 chars)
For a brief moment, I thought this was as short as I could make it, but then...
df"wD+ (6 chars)
As far as I know, this is the shortest possible macro to accomplish this task, but I would love to be proven wrong.
UPDATE:
My friend Chris Sutter has contributed another solution using text objects that is pretty nifty.
di"Vp (5 chars)
or if you want to jump to next line as with the previous 6 char macro:
di"Vgp (6 chars)
Good stuff... thanks Chris!
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3 comments:
:%s/^.*"\(.*\)".*$/\1/
a bit longer, but no macro repetition necessary
I don't like the shorter version you had (df"wD+ (6 chars)), becuase it uses w to go to the next word. If an entry had a non-word character, it wouldn't work. The f" was better in that regard.
However, the di"Vp is brilliant. I have never heard of text objects. Must investigate...
How about:
df";D+
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